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(x)=-5x^2+30x+10
We move all terms to the left:
(x)-(-5x^2+30x+10)=0
We get rid of parentheses
5x^2-30x+x-10=0
We add all the numbers together, and all the variables
5x^2-29x-10=0
a = 5; b = -29; c = -10;
Δ = b2-4ac
Δ = -292-4·5·(-10)
Δ = 1041
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-\sqrt{1041}}{2*5}=\frac{29-\sqrt{1041}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+\sqrt{1041}}{2*5}=\frac{29+\sqrt{1041}}{10} $
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